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Author Question: If X and Y are mutually exclusive events with P(X) = 0.295, P(Y) = 0.32, then P(X Y) = (Read 46 times)

mimie

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on: Mar 25, 2023

Question 1

If X and Y are independent events with P(X) = 0.90 and P(Y) = 0.70, then P(X∩Y) =


◦

0.63


◦

0.95


◦

0.20


◦

1.60



Question 2

If X and Y are mutually exclusive events with P(X) = 0.295, P(Y) = 0.32, then P(X ⏐ Y) =


◦

0.0944


◦

0.6150


◦

1.0000


◦

0.0000

Essentials of Statistics for Business and Economics ¦ Anderson, Sweeney, Williams, Camm, Cochran ¦ 7th Edition
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Marked as best answer by mimie on Mar 25, 2023

bball_babe_123

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Reply #1 on: Mar 25, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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mimie

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Reply 2 on: Mar 25, 2023
Gracias!

covalentbond

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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