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Author Question: A 250. mL sample of 0.0328M HCl is partially neutralized by the addition of 100. mL of 0.0245M NaOH. ... (Read 3 times)

erikka246

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on: Nov 5, 2023

Question 1

A 20.00 mL sample of 0.1015 M nitric acid is introduced into a flask, and water is added until the volume of the solution reaches 250. mL.  What is the concentration of nitric  acid in the final solution?
◦ 1.27 M
◦ 8.12 × 10–3 M
◦ 0.406 M
◦ 3.25 × 10–2 M
◦ 5.08 × 10–4 M

Question 2

A 250. mL sample of 0.0328M HCl is partially neutralized by the addition of 100. mL of 0.0245M NaOH.  Find the concentration of hydrochloric acid in the resulting solution.
◦ 0.00700 M
◦ 0.0164 M
◦ 0.0383 M
◦ 0.0230 M
◦ 0.0575 M
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by erikka246 on Nov 5, 2023

psuniv

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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erikka246

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Reply 2 on: Nov 5, 2023
Excellent

EAN94

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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