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Author Question: Calculate the amount of heat necessary to raise the temperature of 135.0 g of water from 50.4F to ... (Read 93 times)

billyboy7272

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on: Nov 5, 2023

Question 1

Calcium oxide and water react in an exothermic reaction:
         CaO(s) + H2O(l) → Ca(OH)2(s)     ΔH°rxn = –64.8 kJ/mol
How much heat would be liberated when 7.15 g CaO(s) is dropped into a beaker containing 152g H2O?
◦ 1.97 × 10–3 kJ
◦ 8.26 kJ
◦ 508 kJ
◦ 547 kJ
◦ 555 kJ

Question 2

Calculate the amount of heat necessary to raise the temperature of 135.0 g of water from 50.4°F to 85.0°F. The specific heat of water = 4.184 J/g·°C.
◦ 1.1 kJ
◦ 10.9 kJ
◦ 16.6 kJ
◦ 19.5 kJ
◦ 48.0 kJ
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by billyboy7272 on Nov 5, 2023

FireandIce

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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billyboy7272

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Reply 2 on: Nov 5, 2023
Gracias!

skipfourms123

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Reply 3 on: Yesterday
:D TYSM

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