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Author Question: Calculate the concentration of malonate ion (C3H2O42) in a 0.200 M solution of malonic acid ... (Read 7 times)

kandiwilson165@gmail.com

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Question 1

Calculate the concentration of chromate ion (CrO42–) in a 0.450 M solution of chromic acid (H2CrO4). [For chromic acid, Ka1 = 0.18, Ka2 = 3.2 × 10–7.]
◦ 3.2 × 10–7 M
◦ 1.5 × 10–6 M
◦ 0.081 M
◦ 1.1 × 10–6 M
◦ 0.21 M

Question 2

Calculate the concentration of malonate ion (C3H2O42–) in a 0.200 M solution of malonic acid (C3H4O4). [For malonic acid, Ka1 = 1.4 × 10–3, Ka2 = 2.0 × 10–6.]
◦ 2.8 × 10–4 M
◦ 0.016 M
◦ 1.8 × 10–4 M
◦ 1.4 × 10–3 M
◦ 2.0 × 10–6 M


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Marked as best answer by kandiwilson165@gmail.com on Nov 5, 2023

avelasquez

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kandiwilson165@gmail.com

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Reply 2 on: Nov 5, 2023
Wow, this really help


jojobee318

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Reply 3 on: Yesterday
Great answer, keep it coming :)

 

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