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Author Question: Calculate the pH of a 0.021 M NaCN solution. [Ka(HCN) = 4.9 1010] (Read 7 times)

ninaj

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on: Nov 5, 2023

Question 1

Calculate the pH of 2.6 × 10–2 M KOH.
◦ 12.41
◦ 15.59
◦ 2.06
◦ 7.00
◦ 1.59

Question 2

Calculate the pH of a 0.021 M NaCN solution.  [Ka(HCN) = 4.9 × 10–10]
◦ 1.68
◦ 3.18
◦ 5.49
◦ 7.00
◦ 10.82
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Marked as best answer by ninaj on Nov 5, 2023

brunoanthony

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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ninaj

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Reply 2 on: Nov 5, 2023
:D TYSM

nothere

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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