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Author Question: Calculate the pH of a 0.18 M solution of KNO2 (Ka (HNO2) = 4.5 x 10-4) (Read 14 times)

Dannyrod2

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on: Nov 5, 2023

Question 1

Calculate the pH of a 0.14 M HNO2 solution that is 5.7% ionized.
◦ 0.85
◦ 1.70
◦ 2.10
◦ 11.90
◦ 13.10

Question 2

Calculate the pH of a 0.18 M solution of KNO2 (Ka (HNO2) = 4.5 x 10-4)
◦ 5.70
◦ 8.30
◦ 2.05
◦ 11.95
◦ 9.91
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Marked as best answer by Dannyrod2 on Nov 5, 2023

delmiss

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Dannyrod2

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Reply 2 on: Nov 5, 2023
Gracias!

Mochi

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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