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Author Question: Solve the problem.What is the probability that in three consecutive rolls of two fair dice, a person ... (Read 88 times)

theo

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on: Jan 16, 2020
Solve the problem.

What is the probability that in three consecutive rolls of two fair dice, a person gets a total of 7, followed by a total of 11, followed by a total of 7? Round to the nearest ten-thousandth.
◦ 0.1667
◦ 0.0015
◦ 0.0012
◦ 0.2876
Statistics: Informed Decisions Using Data ¦ Sullivan ¦ 5th Edition
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Marked as best answer by theo on Jan 16, 2020

SomethingSomething

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Reply #1 on: Jan 16, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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theo

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Reply 2 on: Jan 16, 2020
Great answer, keep it coming :)

covalentbond

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Reply 3 on: Yesterday
Excellent

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