Author Question: A researcher wishes to test H0: 1 = 2 = 3 against H1:at least one of the means is different. Based ... (Read 73 times)

jrubin · **on:** Jan 16, 2020

A researcher wishes to test H₀: μ₁ = μ₂ = μ₃ against H₁:at least one of the means is different. Based on the ANOVA table below, if the level of significance is α = 0.01, is it necessary to conduct Tukey's test? If the level of significance is α = 0.05, is it necessary to conduct Tukey's test? Explain.

SOURCE

df

SS

MS

F p

______________________________________________________________

Treatments

2

86.22

43.11

13.15 0.0174

Blocks

2 0.889 0.444 0.136 0.8767

Error

4

13.11

3

.28

______________________________________________________________
Total 8 100.22

◦ no, H₀ not rejected; yes, H₀ rejected, at least one mean found to be different
◦ yes, H₀ rejected, at least one mean found to be different; yes, H₀ rejected, at least one mean found to be different
◦ yes, H₀ rejected, at least one mean found to be different ; no, H₀ not rejected
◦ no, H₀ not rejected; no, H₀ not rejected;

Loise Hard · **Reply #1 on:** Jan 16, 2020

A FREE account is required to view all solutions!

Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.

Answer Preview

Only 25% of students answer this correctly