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Author Question: Analyze the following code.class Test { public static void main(String[] args) { String ... (Read 57 times)

Kikoku

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Analyze the following code.

class Test {
public static void main(String[] args) {
String s;
System.out.println("s is " + s);
}
}

◦ The program has a compilation error because s is not initialized, but it is referenced in the println statement.
◦ The program has a runtime error because s is not initialized, but it is referenced in the println statement.
◦ The program compiles and runs fine.
◦ The program has a runtime error because s is null in the println statement.


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Marked as best answer by Kikoku on May 6, 2020

Kdiggy

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Kikoku

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Reply 2 on: May 6, 2020
Thanks for the timely response, appreciate it


hramirez205

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Reply 3 on: Yesterday
:D TYSM

 

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