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Author Question: Consider the following data concerning the equation: H2O2 + 3I + 2H+ I3 + ... (Read 84 times)

charchew

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Consider the following data concerning the equation:
    H2O2 + 3I + 2H+→ I3 + 2H2O
 
[H2O2]
 
[I]
[H+]
rate
I
0.100 M
 
5.00 × 10–4M
1.00 × 10–2M
0.137 M/sec
II.
0.100 M
 
1.00 × 10–3M
1.00 × 10–2M
0.268 M/sec
III.
0.200 M
 
1.00 × 10–3M
1.00 × 10–2M
0.542 M/sec
IV.
0.400 M
 
1.00 × 10–3M
2.00 × 10–2M
1.084 M/sec

The rate law for this reaction is:

 
Reference: Ref 12-2


rate = k[H2O2][I][H+]
rate = k[H2O2]2[I]2[H+]2
rate = k[I][H+]
rate = k[H2O2][H+]
rate = k[H2O2][I]


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Marked as best answer by charchew on Mar 21, 2021

ktidd

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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charchew

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Reply 2 on: Mar 21, 2021
YES! Correct, THANKS for helping me on my review


xiazhe

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Reply 3 on: Yesterday
Great answer, keep it coming :)

 

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