Author Question: Calculate velocity of a vertical projectile with only time? (Read 1267 times)

Jesse_J

  • Sr. Member
  • ****
  • Posts: 282
So for my physics class, one assignment was shown as a video. A ball is shot straight in the air from a launcher, it take a total of 1.37 seconds from the point of being shot till it returns to it's starting place.

The only other info is that the launcher is sitting on a 1 metre tall table.

I need to know the velocity of the projectile, and can't find anything on how to do it anywhere.

Thanks!



Hawke

  • Hero Member
  • *****
  • Posts: 679
v = u+at
v = 0 at max height, t = (1.37/2) at max height , a = -9.81 , u =?
0 = u -9.81 x (1.37/2)
u = 9.81 x (1.37/2)
u = 6.72m/s



Related Topics

Need homework help now?

Ask unlimited questions for free

Ask a Question

Jones

  • Full Member
  • ***
  • Posts: 145
If it takes 1.3s. to return to its start point (1m. above ground), it takes 0.65s. to reach maximum height. So you need to find that height.
Height = 1/2 (t^2 x g), = 2.07025m.
Since you have table height, one must assume you need velocity at GROUND. So, add 1 metre.
Velocity = sqrt. (2gh), = 7.7574m/sec.

9.8 used as g.



 

Did you know?

For pediatric patients, intravenous fluids are the most commonly cited products involved in medication errors that are reported to the USP.

Did you know?

The U.S. Preventive Services Task Force recommends that all women age 65 years of age or older should be screened with bone densitometry.

Did you know?

The ratio of hydrogen atoms to oxygen in water (H2O) is 2:1.

Did you know?

A seasonal flu vaccine is the best way to reduce the chances you will get seasonal influenza and spread it to others.

Did you know?

Calcitonin is a naturally occurring hormone. In women who are at least 5 years beyond menopause, it slows bone loss and increases spinal bone density.

For a complete list of videos, visit our video library