Author Question: Calculate velocity of a vertical projectile with only time? (Read 1497 times)

Jesse_J

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So for my physics class, one assignment was shown as a video. A ball is shot straight in the air from a launcher, it take a total of 1.37 seconds from the point of being shot till it returns to it's starting place.

The only other info is that the launcher is sitting on a 1 metre tall table.

I need to know the velocity of the projectile, and can't find anything on how to do it anywhere.

Thanks!



Hawke

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v = u+at
v = 0 at max height, t = (1.37/2) at max height , a = -9.81 , u =?
0 = u -9.81 x (1.37/2)
u = 9.81 x (1.37/2)
u = 6.72m/s



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Jones

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If it takes 1.3s. to return to its start point (1m. above ground), it takes 0.65s. to reach maximum height. So you need to find that height.
Height = 1/2 (t^2 x g), = 2.07025m.
Since you have table height, one must assume you need velocity at GROUND. So, add 1 metre.
Velocity = sqrt. (2gh), = 7.7574m/sec.

9.8 used as g.



 

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