The net force acting on a 4.92-kg object is given by Fx = (10 x) ...

[j.rubin]

The net force acting on a 4.92-kg object is given by Fx = (10  x) N, where Fx is in newtons and x is in meters. How much work is done on the object as it moves from x = 0 to x = 12.4 m?
 a. 61.0 J
  b. 12.4 J
  c. 47.1 J
  d. 23.6 J
  e. 35.3 J

Question 2

The force acting on an object is given by Fx = (5x  10) N, where x is in meters. What is the net work done by the force as the object moves from x = 0 to x = 4.50?
 a. 5.6 J
  b. 15.6 J
  c. 12.5 J
  d. 11.3 J

[Kingjoffery]

Answer to Question 1

c

Answer to Question 2

a

[j.rubin]

TYSM

[amit]

Gracias!