A force acting on a 2.00 kg object is given by F(x) = (2.00 N/m)x ...

[Chelseaamend]

A force acting on a 2.00 kg object is given by F(x) = (2.00 N/m)x + (1.00 N/m3)x3. An object starts at rest at x = 1.00 m. What is speed of the object when it reaches x = 2.00 m?
 
  A)
 
  1.23 m/s
  B)
 
  0.650 m/s
  C)
 
  2.60 m/s
  D)
 
  1.78 m/s
  E)
 
  The object does not reach 2.00 m because the increase in potential energy would imply a negative kinetic energy.

Question 2

If the image distance is negative, the image formed by a mirror is a(n)
 
  A)
 
  real image.
  B)
 
  virtual image.
  C)
 
  imaginary image.
  D)
 
  positive image.
  E)
 
  negative image.

[SamMuagrove]

Answer to Question 1

C

Answer to Question 2

B

[Chelseaamend]

Gracias!

[epscape]

Excellent