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Author Question: Light of intensity S0 that is polarized horizontally passes through three ideal polarizers. The ... (Read 147 times)

Evvie72

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on: Oct 11, 2019

Question 1

As shown in the figure, the orientation of the transmission axis for each of three ideal polarizing sheets is labeled relative to the vertical direction. A beam of light, polarized in the vertical direction, is incident on the first polarizer with an intensity of 1.00 kW/m2. What is the intensity of the beam after it has passed through the three polarizing sheets when θ1 = 30°, θ2 = 30°, and θ3= 60°?


◦ 433 W/m2
◦ 188 W/m2
◦ 563 W/m2
◦ 316 W/m2
◦ 141 W/m2

Question 2

Light of intensity S0 that is polarized horizontally passes through three ideal polarizers. The first and third are horizontal, but the second one is oriented at to the horizontal. In terms of S0, the intensity of the light that passes through the set of polarizers is closest to which one of the following choices?
◦ 0.427 S0
◦ 0.125 S0
◦ 0.729 S0
◦ 0.854 S0
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Marked as best answer by Evvie72 on Oct 11, 2019

duke02

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Reply #1 on: Oct 11, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Evvie72

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Reply 2 on: Oct 11, 2019
Great answer, keep it coming :)

shewald78

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Reply 3 on: Yesterday
Wow, this really help

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