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Author Question: A waiting-line system that meets the assumptions of M/M/1 has = 1, = 4. For this system, the ... (Read 27 times)

eruditmonkey@yahoo.com

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on: Dec 3, 2019

Question 1

A waiting-line system that meets the assumptions of M/M/S has λ = 5, μ = 4, and M = 2. For these values, Po is approximately 0.23077 and Ls is approximately 2.05128. The average number of units waiting in the queue
◦ is approximately 1.0417.
◦ is approximately 0.8013.
◦ is approximately 0.1603.
◦ is approximately 0.4103.
◦ cannot be calculated because λ is larger than μ.

Question 2

A waiting-line system that meets the assumptions of M/M/1 has λ = 1, μ = 4. For this system, the probability of more than two units in the system is approximately
◦ 0.0625.
◦ zero.
◦ 0.9375.
◦ 0.015625.
◦ 0.25.
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Marked as best answer by eruditmonkey@yahoo.com on Dec 3, 2019

leahchrapun

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Reply #1 on: Dec 3, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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eruditmonkey@yahoo.com

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Reply 2 on: Dec 3, 2019
Great answer, keep it coming :)

kjohnson

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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