A waiting-line system that meets the assumptions of M/M/1 has = ...

[eruditmonkey@yahoo.com]

Question 1

A waiting-line system that meets the assumptions of M/M/S has λ = 5, μ = 4, and M = 2. For these values, Po is approximately 0.23077 and Ls is approximately 2.05128. The average number of units waiting in the queue
◦ is approximately 1.0417.
◦ is approximately 0.8013.
◦ is approximately 0.1603.
◦ is approximately 0.4103.
◦ cannot be calculated because λ is larger than μ.

Question 2

A waiting-line system that meets the assumptions of M/M/1 has λ = 1, μ = 4. For this system, the probability of more than two units in the system is approximately
◦ 0.0625.
◦ zero.
◦ 0.9375.
◦ 0.015625.
◦ 0.25.

[leahchrapun]

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[eruditmonkey@yahoo.com]

Wow, this really help

[phuda]

Thanks for the timely response, appreciate it