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Author Question: Consider the following reduction potentials: Cu2+ + 2e Cu E = 0.339 V Pb2+ + 2e Pb E = ... (Read 305 times)

rayancarla1

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on: Mar 21, 2021
Consider the following reduction potentials:

    Cu2+ + 2e– Cu          E° = 0.339 V

    Pb2+ + 2e– Pb          E° = –0.130 V

For a galvanic cell employing the Cu, Cu2+ and Pb, Pb2+ couples, calculate the maximum amount of work that would accompany the reaction of one mole of lead under standard conditions.


◦ –40.3 kJ
◦ –45.3 kJ
◦ –90.5 kJ
◦ No work can be done. The system is at equilibrium.
◦ None of these are correct.
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by rayancarla1 on Mar 21, 2021

soda0602

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Danilyn C. Densing

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Reply #2 on: Apr 17, 2021
TY


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