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Author Question: Consider the following standard reduction potentials,Zn2+(aq) + 2 e- Zn(s)E = -0.76 VI2(s) + 2 e- ... (Read 145 times)

tichca

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on: Feb 15, 2020
Consider the following standard reduction potentials,

Zn2+(aq) + 2 e- → Zn(s)E° = -0.76 V
I2(s) + 2 e- → 2 I-(aq)E° = +0.54 V

Under standard conditions,
◦ Zn2+(aq) is a stronger oxidizing agent than I2(s) and I-(aq) is a stronger reducing agent than Zn(s).
◦ I-(aq) is a stronger oxidizing agent than Zn(s) and I2(s) is a stronger reducing agent than Zn2+(aq).
◦ Zn(s) is a stronger oxidizing agent than I-(aq) and Zn2+(aq) is a stronger reducing agent than I2(s).
◦ I2(s) is a stronger oxidizing agent than Zn2+(aq) and Zn(s) is a stronger reducing agent than I-(aq).
Chemistry ¦ McMurry, Fay, Robinson ¦ 7th Edition
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Marked as best answer by tichca on Feb 15, 2020

Expo

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Reply #1 on: Feb 15, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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tichca

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Reply 2 on: Feb 15, 2020
Wow, this really help

TheDev123

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Reply 3 on: Yesterday
Gracias!

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