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Author Question: What is the approximate pH at the equivalence point of a weak acid-strong base titration if 25 mL of ... (Read 73 times)

jayhills49

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on: Feb 15, 2020

Question 1

What is the approximate pH at the equivalence point of a weak acid-strong base titration if 25 mL of aqueous formic acid requires 29.80 mL of 0.2567 M NaOH? Ka = 1.8 × 10-4 for formic acid.
◦ 8.44
◦ 5.56
◦ 2.13
◦ 11.87

Question 2

What is the approximate pH at the equivalence point of a weak acid-strong base titration if 25 mL of aqueous hydrofluoric acid requires 30.00 mL of 0.100 M NaOH?  Ka = 6.76 × 10-4 for HF.
◦ 2.05
◦ 7.95
◦ 6.05
◦ 11.95
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Marked as best answer by jayhills49 on Feb 15, 2020

apple

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Reply #1 on: Feb 15, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jayhills49

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Reply 2 on: Feb 15, 2020
Wow, this really help

Zebsrer

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Reply 3 on: Yesterday
:D TYSM

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