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Author Question: The latent heat of melting is 80 calories for 1 gram of ice. If 1 gram of ice absorbs 120 calories, ... (Read 303 times)

azncindy619

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on: Feb 28, 2020
The latent heat of melting is 80 calories for 1 gram of ice. If 1 gram of ice absorbs 120 calories, what is the result?
◦ 1 gram of water at a temperature of 120°C
◦ a mixture of ice and water at a temperature of 0°C
◦ 1 gram of water at a temperature of 40°C
◦ 1 gram of water at a temperature of 20°C
◦ a mixture of water and steam at a temperature of 120°C
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Marked as best answer by azncindy619 on Feb 28, 2020

okolip

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Reply #1 on: Feb 28, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Ana Fernandez

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Reply #2 on: Dec 5, 2021
thank you
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