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Author Question: Aluminum Rod#1 has a length L and a diameter d. Aluminum Rod#2 has a length 2L and a diameter 2d. If ... (Read 150 times)

roselinechinyere27m

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on: Aug 6, 2020
Aluminum Rod#1 has a length L and a diameter d. Aluminum Rod#2 has a length 2L and a diameter 2d. If Rod#1 is under tension T and Rod#2 is under tension 2T, how do the changes in length of the two rods compare?

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They are the same.

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Rod#1 has double the change in length that Rod#2 has.

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Rod#2 has double the change in length that Rod#1 has.

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Rod#1 has quadruple the change in length that Rod#2 has.

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Rod#2 has quadruple the change in length that Rod#1 has.
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by roselinechinyere27m on Aug 6, 2020

tennis14576

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Reply #1 on: Aug 6, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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roselinechinyere27m

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Reply 2 on: Aug 6, 2020
:D TYSM

rleezy04

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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