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Author Question: Consider the hydrogenoxygen fuel cell where:H2(g) + O2(g) H2O(l) G = 237.18 kJ/mol H2Which of ... (Read 51 times)

dalyningkenk

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on: Mar 21, 2021
Consider the hydrogen–oxygen fuel cell where:

H2(g) + ½O2(g) H2O(l)          ΔG° = –237.18 kJ/mol H2

Which of the following statements is false?


◦ At standard conditions, the maximum work the fuel cell could do on the surroundings is 237.18 kJ/mol.
◦ In the real world, the actual amount of useful work the cell can do is more than 237.18 kJ.
◦ More energy is dissipated as waste heat in the fuel cell than in the reversible pathway.
◦ The reaction is spontaneous and has a positive cell potential.
◦ All of these are true.
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by dalyningkenk on Mar 21, 2021

gabrielle_lawrence

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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dalyningkenk

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Reply 2 on: Mar 21, 2021
Gracias!

nguyenhoanhat

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Reply 3 on: Yesterday
:D TYSM

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