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Author Question: Find the maximum and minimum values of the function f(x, y, z, u, v) = x2+ y2 + z2 + u2 + v2 subject ... (Read 148 times)

haleyc112

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on: May 27, 2021
Find the maximum and minimum values of the function  f(x, y, z, u, v) = x2+ y2 + z2 + u2 + v2  subject to the constraints x + y + 3z = 7 and 3z - u -v = 13.
◦ maximum 19, occurs at the point (x, y, z, u, v) = (- 1, -1, 3, -2, -2) and no minimum value
◦ minimum 0, occurs at the point (x, y, z, u, v) = (0, 0, 0, 0, 0) and no maximum value
◦ maximum 89, occurs at the point (x, y, z, u, v) = (1, 1, -9, 2, 2) and no minimum value
◦ minimum 19, occurs at the point (x, y, z, u, v) = (- 1,- 1, 3, -2, -2) and no maximum value
◦ There are no finite extreme values.
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Marked as best answer by haleyc112 on May 27, 2021

meow1234

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Reply #1 on: May 27, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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haleyc112

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Reply 2 on: May 27, 2021
YES! Correct, THANKS for helping me on my review

elyse44

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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