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Author Question: Solve the initial-value problem + 4 = 0, y(1)= 1, y'(1) = 2. (Read 156 times)

Jkov05

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Question 1

Solve the initial-value problem y" + 8y' + 16y = 0;  y(0) = 3,  y'(0) = 1.
◦ y = (13t - 3)e-4t
◦ y = (7t + 1)e-4t
◦ y = (7t - 1)e4t
◦ y = (13t + 3)e-4t
◦ y = (13t + 3)e4t

Question 2

Solve the initial-value problem   + 4 = 0,   y(1)= 1,  y'(1) = 2.
◦ y = - e4(1 - x)
◦ y = - e-3x
◦ y = - e4 e4x
◦ y = - e4(1 - x)
◦ y = - e4(1 - x)


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Marked as best answer by Jkov05 on May 27, 2021

Benayers

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Jkov05

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Reply 2 on: May 27, 2021
Thanks for the timely response, appreciate it


zacnyjessica

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Reply 3 on: Yesterday
Gracias!

 

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