Author Question: Determine where the given function is increasing and where it is decreasing.f(x) = 2x3- 15x2+ 24x (Read 42 times)

dejastew · **on:** Jun 16, 2021

Question 1

Determine where the given function is increasing and where it is decreasing.

f(x) = -x³ + 3x² - 10
◦ Decreasing on (-∞, -1) and (1, ∞), increasing on (-1, 1)
◦ Increasing on (-∞, 0) and (2, ∞), decreasing on (0, 2)
◦ Decreasing on (-∞, 0) and (2, ∞), increasing on (0, 2)
◦ Decreasing on (-∞, 2), increasing on (2, ∞)

Question 2

Determine where the given function is increasing and where it is decreasing.

f(x) = 2x3 - 15x2 + 24x
◦ Increasing on (-∞, 1) and (4, ∞), decreasing on (1, 4)
◦ Decreasing on (-∞, 1) and (4, ∞), increasing on (1, 4)
◦ Increasing on (-∞, 1), decreasing on (1, ∞)
◦ Decreasing on (-∞, 0) and (4, ∞), increasing on (0, 4)

bookworm410 · **Reply #1 on:** Jun 16, 2021

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.

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