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Author Question: How many millilitres of 0.120 mol L-1 NaOH(aq) are required to titrate 50.0 mL of 0.0998 mol L-1 ... (Read 67 times)

kellyjaisingh

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on: Jul 8, 2021

Question 1

How many millilitres of 0.0850 mol L-1 NaOH(aq) are required to titrate 25.0 mL of (aq) to the equivalence point?
◦ 21.2
◦ 0.245
◦ 3.92
◦ 0.153
◦ 29.5

Question 2

How many millilitres of 0.120 mol L-1 NaOH(aq) are required to titrate 50.0 mL of 0.0998 mol L-1 aqueous butanoic acid to the equivalence point? Butanoic acid is monoprotic. The Ka of butanoic acid is 1.5 × 10-5.
◦ 4.90
◦ 50.0
◦ 41.6
◦ 60.1
◦ 4.65
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by kellyjaisingh on Jul 8, 2021

okolip

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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kellyjaisingh

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Reply 2 on: Jul 8, 2021
Excellent

recede

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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