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Author Question: How many millilitres of 0.0890 mol L-1 NaOH are required to titrate 25.0 mL of 0.0680 to the ... (Read 72 times)

colton

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on: Nov 18, 2019

Question 1

What is the pH of a solution made by mixing 25.00 mL of 0.100 mol L-1 HCl with 40.00 mL of 0.100 mol L-1 KOH? Assume that the volumes of the solutions are additive.
◦ 1.64
◦ 13.36
◦ 12.36
◦ 0.64

Question 2

How many millilitres of 0.0890 mol L-1 NaOH are required to titrate 25.0 mL of 0.0680 to the equivalence point?
◦ 0.151
◦ 19.1
◦ 3.49
◦ 32.7
◦ 0.242
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Marked as best answer by colton on Nov 18, 2019

31809pancho

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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colton

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Reply 2 on: Nov 18, 2019
Great answer, keep it coming :)

amcvicar

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Reply 3 on: Yesterday
Gracias!

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