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Author Question: By applying the rules DS and DN to ~ (B v C) v (C D), B v C we can deduce (6.) (I ~ D) ~L What is ... (Read 73 times)

Ale

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on: May 12, 2022

Question 1

By applying the rules MT and DN to“~ F ⊃ (~ L v M), ~ (~ L v M)” we can deduce
◦ ~ L v M)
◦ F
◦ ~ F

Question 2

By applying the rules DS and DN to “~ (B v C) v (C ≡ D), B v C” we can deduce (6.) (I ∙ ~ D) ∙ ~L What is the justification for line 3?
◦ 1, 3 MP
◦ 1, 3 Bicond
◦ 2 Simp
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Marked as best answer by Ale on May 12, 2022

MistyHubbard

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Reply #1 on: May 12, 2022
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Ale

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Reply 2 on: May 12, 2022
Thanks for the timely response, appreciate it

alexanderhamilton

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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