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Author Question: By applying the rules Com and DN to ~ ~ B v ~ ~ A we can deduce (Read 13 times)

Darron12

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on: May 12, 2022

Question 1

By applying the rules Bicond and DN to “B ≡ ~ A” we can deduce
◦ (B ∙ ~ A) v (~ B ∙ A)
◦ (~ B ∙ ~ A) v (~ B ∙ A)
◦ (B ∙ ~ A) v (~ B ∙ ~ A)

Question 2

By applying the rules Com and DN to “~ ~ B v ~ ~ A” we can deduce
◦ ~ A v ~ B
◦ A v ~ B
◦ A v B
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Marked as best answer by Darron12 on May 12, 2022

msgero

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Reply #1 on: May 12, 2022
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Darron12

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Reply 2 on: May 12, 2022
YES! Correct, THANKS for helping me on my review

vickybb89

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Reply 3 on: Yesterday
Excellent

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