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Author Question: How many grams of Cl2 can be prepared from the reaction of 16.0 g of MnO2 and 30.0 g of HCl ... (Read 43 times)

Sadjam2

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on: Nov 5, 2023

Question 1

How many fluorine atoms are there in 65 g of CF4?
◦ 0.74 atoms
◦ 3.0 atoms
◦ 4.5 × 1023 atoms
◦ 1.8 × 1024 atoms
◦ 2.4 × 1023 atoms

Question 2

How many grams of Cl2 can be prepared from the reaction of 16.0 g of MnO2 and 30.0 g of HCl according to the following chemical equation?
         MnO2 + 4HCl → MnCl2 + Cl2 + 2H2O
◦ 0.82 g
◦ 5.8 g
◦ 13.0 g
◦ 14.6 g
◦ 58.4 g
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by Sadjam2 on Nov 5, 2023

lactosetheintolerant

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Sadjam2

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Reply 2 on: Nov 5, 2023
Gracias!

JaynaD87

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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