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Author Question: The bond enthalpy of the BrCl bond is equal to H for the reaction BrCl(g) Br(g) + Cl(g).Use the ... (Read 11 times)

Austinleez3

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The bond enthalpy of the Br–Cl bond is equal to ΔH° for the reaction
         BrCl(g) → Br(g) + Cl(g).
Use the following data to find the bond enthalpy of the Br–Cl bond.
Br2(l) → Br2(g)
ΔH° = 30.91 kJ/mol
Br2(g) → 2Br(g)
ΔH° = 192.9 kJ/mol
Cl2(g) → 2Cl(g)
ΔH° = 243.4 kJ/mol
Br2(l) + Cl2(g) → 2BrCl(g)
ΔH° = 29.2 kJ/mol
 

◦ 14.6 kJ/mol
◦ 203.5 kJ/mol
◦ 219.0 kJ/mol
◦ 438.0 kJ/mol
◦ 407.0 kJ/mol


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Marked as best answer by Austinleez3 on Nov 5, 2023

athenaheim

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Austinleez3

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Reply 2 on: Nov 5, 2023
Thanks for the timely response, appreciate it


duy1981999

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Reply 3 on: Yesterday
Great answer, keep it coming :)

 

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