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Author Question: In general, to calculate the activation energy for an elementary step given the rate constants at ... (Read 13 times)

shivanipalawai@gmail.com

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Question 1

If Ea for a certain biological reaction is 50. kJ/mol, by what factor (how many times) will the rate of this reaction increase when body temperature increases from 37°C (normal) to 40°C (fever)?
◦ 1.15
◦ 1.20
◦ 2.0 × 105

◦ 1.0002
◦ 2.0

Question 2

In general, to calculate the activation energy for an elementary step given the rate constants at two different temperatures, which equation should be used?
◦ ln([A]t/[A]o) = – kt
◦ t1/2 = ln2/k
◦ ln(k1/k2) = Ea/R( (T1– T2)/T1T2)
◦ 1/[A]t = kt + 1/[A]o

◦ Rate = k[A]


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Marked as best answer by shivanipalawai@gmail.com on Nov 5, 2023

GoldenBrown

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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shivanipalawai@gmail.com

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Reply 2 on: Nov 5, 2023
Great answer, keep it coming :)


flexer1n1

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

 

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