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Author Question: The solubility of lead(II) iodide is 0.064 g/100 mL at 20C. What is the solubility product for ... (Read 60 times)

emoedee

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on: Nov 5, 2023

Question 1

The pH at the equivalence point of a titration may differ from 7.0 due to
◦ the initial concentration of the standard solution.
◦ the indicator used.
◦ the self-ionization of H2O.
◦ the initial pH of the unknown.
◦ hydrolysis of the salt formed.

Question 2

The solubility of lead(II) iodide is 0.064 g/100 mL at 20ºC.  What is the solubility product for lead(II) iodide?
◦ 1.1 × 10–8

◦ 3.9 × 10–6

◦ 1.1 × 10–11

◦ 2.7 × 10–12

◦ 1.4 × 10–3
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by emoedee on Nov 5, 2023

Kevin5!

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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emoedee

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Reply 2 on: Nov 5, 2023
Wow, this really help

LVPMS

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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