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Author Question: The solubility of lead(II) iodide is 0.064 g/100 mL at 20C. What is the solubility product for ... (Read 28 times)

emoedee

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Question 1

The pH at the equivalence point of a titration may differ from 7.0 due to
◦ the initial concentration of the standard solution.
◦ the indicator used.
◦ the self-ionization of H2O.
◦ the initial pH of the unknown.
◦ hydrolysis of the salt formed.

Question 2

The solubility of lead(II) iodide is 0.064 g/100 mL at 20ºC.  What is the solubility product for lead(II) iodide?
◦ 1.1 × 10–8

◦ 3.9 × 10–6

◦ 1.1 × 10–11

◦ 2.7 × 10–12

◦ 1.4 × 10–3


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Marked as best answer by emoedee on Nov 5, 2023

Kevin5!

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emoedee

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Reply 2 on: Nov 5, 2023
Wow, this really help


amandalm

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

 

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