Author Question: Draw Fischer projections for these compounds. ... (Read 23 times)

laurencescou · **on:** Aug 23, 2018

Draw Fischer projections for these compounds.

Question 2

Draw all the stereoisomers of 3-penten-2-ol

Question 3

Draw all the stereoisomers of 1, 2-dimethylcyclopentane.

Question 4

The alkane formed by hydrogenation of (S)-4-methyl-l-hexene is optically active while the one formed by
hydrogenation of (S)-3-methyl-l-pentene is not. Explain.

taylorsonier · **Reply #1 on:** Aug 23, 2018

Answer to Question 1

Answer to Question 2

Answer to Question 3

Answer to Question 4

Each starting alkene is optically active because it contains a stereogenic centera carbon with four
different groups bonded to it. The alkane formed by the hydrogenation of (S)-4-methyl-l-hexene is optically
because carbon four is still chiral. The product of hydrogenation of (S)-3-methyl-l-pentene is not optically
active because two of the groups on carbon three are the same nowthey are ethyl groups.