Draw Fischer projections for these compounds. ...

[laurencescou]

Draw Fischer projections for these compounds.
 

Question 2

Draw all the stereoisomers of 3-penten-2-ol
 

Question 3

Draw all the stereoisomers of 1, 2-dimethylcyclopentane.

Question 4

The alkane formed by hydrogenation of (S)-4-methyl-l-hexene is optically active while the one formed by
  hydrogenation of (S)-3-methyl-l-pentene is not. Explain.

[taylorsonier]

Answer to Question 1



Answer to Question 2



Answer to Question 3



Answer to Question 4

Each starting alkene is optically active because it contains a stereogenic centera carbon with four
different groups bonded to it. The alkane formed by the hydrogenation of (S)-4-methyl-l-hexene is optically
because carbon four is still chiral. The product of hydrogenation of (S)-3-methyl-l-pentene is not optically
active because two of the groups on carbon three are the same nowthey are ethyl groups.

[laurencescou]

TYSM

[at]

Great answer, keep it coming