[Answered] The center of a circle defined by the equation (x-3)2 + (y+5)2 = 9 is located at the point:

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Author Question: The center of a circle defined by the equation (x-3)2 + (y+5)2 = 9 is located at the point: (Read 29 times)

jhjkgdfhk

Hero Member
Posts: 569

on: Oct 14, 2019

Question 1

For a parabola y = a(x-h)2 + k, if a is a positive number then the parabola opens:

◦

to the left.

◦

to the right.

◦

down.

◦

up.

Question 2

The center of a circle defined by the equation (x-3)2 + (y+5)2 = 9 is located at the point:

◦

(-3,5).

◦

(-3,-5).

◦

(3,-5).

◦

(3,5).

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Marked as best answer by jhjkgdfhk on Oct 14, 2019

ergserg

Sr. Member
Posts: 338

Reply #1 on: Oct 14, 2019

Answer 1

up.

Answer 2

(3,-5).

jhjkgdfhk

Member
Posts: 569

Reply 2 on: Oct 14, 2019

YES! Correct, THANKS for helping me on my review

dreamfighter72

Member
Posts: 355

Reply 3 on: Yesterday

Gracias!

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Author Question: The center of a circle defined by the equation (x-3)2 + (y+5)2 = 9 is located at the point: (Read 29 times)

jhjkgdfhk

The center of a circle defined by the equation (x-3)2 + (y+5)2 = 9 is located at the point:

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Need homework help now?

ergserg

The center of a circle defined by the equation (x-3)2 + (y+5)2 = 9 is located at the point:

jhjkgdfhk

dreamfighter72