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Author Question: The center of a circle defined by the equation (x-3)2 + (y+5)2 = 9 is located at the point: (Read 69 times)

jhjkgdfhk

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on: Oct 14, 2019

Question 1

For a parabola y = a(x-h)2 + k, if a is a positive number then the parabola opens:


◦

to the left.


◦

to the right.


◦

down.


◦

up.



Question 2

The center of a circle defined by the equation (x-3)2 + (y+5)2 = 9 is located at the point:


◦

(-3,5).


◦

(-3,-5).


◦

(3,-5).


◦

(3,5).



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Marked as best answer by jhjkgdfhk on Oct 14, 2019

ergserg

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Reply #1 on: Oct 14, 2019

Answer 1

up.



Answer 2

(3,-5).



jhjkgdfhk

  • Member
  • Posts: 569
Reply 2 on: Oct 14, 2019
YES! Correct, THANKS for helping me on my review

JCABRERA33

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  • Posts: 344
Reply 3 on: Yesterday
Great answer, keep it coming :)

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