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Author Question: When 31.2 mL of 0.500 mol L-1 AgNO3 is added to 25.0 mL of 0.300 mol L-1 NH4Cl, how many grams of ... (Read 121 times)

kshipps

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Question 1

How many grams of CaCl2 are formed when 15.00 mL of 0.00237 mol L-1 Ca(OH)2 reacts with excess Cl2 gas?

2Ca(OH)2(aq) + 2Cl2(g) → Ca(OCl)2(aq) + CaCl2(s) + 2H2O(l)

◦ 0.00197 g
◦ 0.00394 g
◦ 0.0507 g
◦ 0.00789 g

Question 2

When 31.2 mL of 0.500 mol L-1 AgNO3 is added to 25.0 mL of 0.300 mol L-1 NH4Cl, how many grams of AgCl are formed?

AgNO3(aq) + NH4Cl(aq) → AgCl(s) + NH4NO3(aq)

◦ 1.07 g
◦ 3.31 g
◦ 6.44 g
◦ 2.24 g


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Marked as best answer by kshipps on Nov 18, 2019

smrtceo

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kshipps

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Reply 2 on: Nov 18, 2019
:D TYSM


parker125

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Reply 3 on: Yesterday
Excellent

 

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