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Author Question: What volume of benzene (C6H6, d = 0.88 g mL-1, molar mass = 78.11 g mol-1) is required to produce ... (Read 178 times)

BrownTown3

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on: Nov 18, 2019

Question 1

Using the following equation for the combustion of octane, calculate the amount of grams of carbon dioxide formed from 100.0 g of octane. The molar mass of octane is 114.33 g mol-1. The molar mass of carbon dioxide is 44.0095 g mol-1.
 
2C8H18 + 25O2 → 16CO2 + 18H2ODrH° = -11018 kJ

◦ 307.9 g
◦ 260.1 g
◦ 792.3 g
◦ 800.1 g

Question 2

What volume of benzene (C6H6, d = 0.88 g mL-1, molar mass = 78.11 g mol-1) is required to produce 1.5 × 103 kJ of heat according to the following reaction?

2C6H6(l) + 15O2(g) → 12CO2(g) + 6H2O(g)DrH° = -6278 kJ

◦ 42 mL
◦ 37 mL
◦ 21 mL
◦ 75 mL
◦ 19 mL
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Marked as best answer by BrownTown3 on Nov 18, 2019

annierak

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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BrownTown3

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Reply 2 on: Nov 18, 2019
Thanks for the timely response, appreciate it

miss_1456@hotmail.com

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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