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Author Question: An electron has a velocity of 6.0 106 m/s in the positive x direction at a point where the magnetic ... (Read 78 times)

saliriagwu

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on: Aug 6, 2020

Question 1

An electron follows a circular path (radius = 15 cm) in a uniform magnetic field (magnitude = 3.0 G). What is the period of this motion?

◦
0.12 μs

◦
1.2 ms

◦
0.18 μs

◦
1.8 ms

◦
1.8 μs


Question 2

An electron has a velocity of 6.0 × 106 m/s in the positive x direction at a point where the magnetic field has the components Bx = 3.0 T, By = 1.5 T, and Bz = 2.0 T. What is the magnitude of the acceleration of the electron at this point?

◦
2.1 × 1018 m/s2

◦
1.6 × 1018 m/s2

◦
2.6 × 1018 m/s2

◦
3.2 × 1018 m/s2

◦
3.7 × 1018 m/s2
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by saliriagwu on Aug 6, 2020

stallen

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Reply #1 on: Aug 6, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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saliriagwu

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Reply 2 on: Aug 6, 2020
Wow, this really help

ASDFGJLO

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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