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Author Question: The vapor pressure of water at 90C is 0.692 atm. What is the vapor pressure (in atm) of a solution ... (Read 68 times)

misspop

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on: Mar 21, 2021

Question 1

The vapor pressure of water at 25.0°C is 23.8 torr. Determine the mass of glucose (molar mass = 180 g/mol) needed to add to 500.0 g of water to change the vapor pressure to 23.1 torr.

◦ 15.2 g
◦ 151 g
◦ 126 g
◦ 6.29 kg
◦ 185 g

Question 2

The vapor pressure of water at 90°C is 0.692 atm. What is the vapor pressure (in atm) of a solution made by dissolving 3.68 mole(s) of CsF(s) in 1.00 kg of water? Assume that Raoult's law applies.

◦ 0.649 atm
◦ 0.784 atm
◦ 0.611 atm
◦ 0.692 atm
◦ none of these are correct
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Marked as best answer by misspop on Mar 21, 2021

Benayers

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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misspop

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Reply 2 on: Mar 21, 2021
Excellent

raenoj

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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