Tabulated below are initial rate data for the reaction ...

[bobypop]

Question 1

Tabulated below are initial rate data for the reaction:
              2Fe(CN)₆^3– + 2I^–→ 2Fe(CN)₆^4– + I₂

Run	[Fe(CN)63–]0	[I–]0	[Fe(CN)64–]0	[I2]0	Rate (M/s)
1	0.01	0.01	0.01	0.01	1 × 10–5
2	0.01	0.02	0.01	0.01	2 × 10–5
3	0.02	0.02	0.01	0.01	8 × 10–5
4	0.02	0.02	0.02	0.01	8 × 10–5
5	0.02	0.02	0.02	0.02	8 × 10–5

What is the value of k?

◦ 10⁷M^–5 s^–1
◦ 10³M^–3 s^–1
◦ 10 M^–2 s^–1
◦ 50 M^–2 s^–1
◦ None of these are correct.

Question 2

Tabulated below are initial rate data for the reaction
              2Fe(CN)₆^3– + 2I^–→ 2Fe(CN)₆^4– + I₂

					Initial
Run	[Fe(CN)63–]0	[I–]0	[Fe(CN)64–]0	[I2]0	Rate (M/s)
1	0.01	0.01	0.01	0.01	1 × 10–5
2	0.01	0.02	0.01	0.01	2 × 10–5
3	0.02	0.02	0.01	0.01	8 × 10–5
4	0.02	0.02	0.02	0.01	8 × 10–5
5	0.02	0.02	0.02	0.02	8 × 10–5

The experimental rate law is:

◦ = k[Fe(CN)₆^3–]²[I^–]²[Fe(CN)₆^4–]²[I₂]
◦ = k[Fe(CN)₆^3–]²[I^–][Fe(CN)₆^4–][I₂]
◦ = k[Fe(CN)₆^3–)]²[I^–]
◦ = k[Fe(CN)₆^3–][I^–]²

◦ = k[Fe(CN)₆^3–][I^–] [Fe(CN)₆^4–]

[princessflame2016]

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[bobypop]

Great answer, keep it coming

[nathang24]

YES! Correct, THANKS for helping me on my review