Question 1
Tabulated below are initial rate data for the reaction:
2Fe(CN)63– + 2I–→ 2Fe(CN)64– + I2
Run | [Fe(CN)63–]0 | [I–]0 | [Fe(CN)64–]0 | [I2]0 | Rate (M/s) |
1 | 0.01 | 0.01 | 0.01 | 0.01 | 1 × 10–5 |
2 | 0.01 | 0.02 | 0.01 | 0.01 | 2 × 10–5 |
3 | 0.02 | 0.02 | 0.01 | 0.01 | 8 × 10–5 |
4 | 0.02 | 0.02 | 0.02 | 0.01 | 8 × 10–5 |
5 | 0.02 | 0.02 | 0.02 | 0.02 | 8 × 10–5 |
What is the value of k?
◦
107M–5 s–1◦
103M–3 s–1◦
10 M–2 s–1◦
50 M–2 s–1◦
None of these are correct.Question 2
Tabulated below are initial rate data for the reaction
2Fe(CN)63– + 2I–→ 2Fe(CN)64– + I2
| | | | | Initial |
Run | [Fe(CN)63–]0 | [I–]0 | [Fe(CN)64–]0 | [I2]0 | Rate (M/s) |
1 | 0.01 | 0.01 | 0.01 | 0.01 | 1 × 10–5 |
2 | 0.01 | 0.02 | 0.01 | 0.01 | 2 × 10–5 |
3 | 0.02 | 0.02 | 0.01 | 0.01 | 8 × 10–5 |
4 | 0.02 | 0.02 | 0.02 | 0.01 | 8 × 10–5 |
5 | 0.02 | 0.02 | 0.02 | 0.02 | 8 × 10–5 |
The experimental rate law is:
◦
= k[Fe(CN)63–]2[I–]2[Fe(CN)64–]2[I2]◦
= k[Fe(CN)63–]2[I–][Fe(CN)64–][I2]◦
= k[Fe(CN)63–)]2[I–]◦
= k[Fe(CN)63–][I–]2
◦
= k[Fe(CN)63–][I–] [Fe(CN)64–]