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Author Question: The following data were obtained for the reaction 2A + B C where rate = [C]/t[A](M)[B](M)Initial ... (Read 20 times)

vinney12

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Question 1

The following data were obtained at 25°C:
 
 
[A]0
[B]0
[C]0
Rate
 
 
0.1
0.2
0.3
0.063
 
 
0.3
0.4
0.2
0.084
 
 
0.6
0.4
0.2
0.168
 
 
0.3
0.4
0.1
0.021
 
 
0.6
0.2
0.2
0.168
What is the correct rate law?


Rate = k[A][B][C]
Rate = k[A][B][C]2

Rate = k[A][C]
Rate = k[A]3[B]2[C]
Rate = k[A][C]2


Question 2

The following data were obtained for the reaction 2A + B → C where rate = Δ[C]/Δt
 
 
[A](M)
[B](M)
Initial Rate (M/s)
 
 
0.100
 
0.0500
2.13 × 10–4
 
 
0.200
 
0.0500
1.70 × 10–2
 
 
0.400
 
0.100
1.36 × 10–1
What is the value of the rate constant?


2.13
0.213
0.426
1.70
None of these are correct.


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Marked as best answer by vinney12 on Mar 21, 2021

djpooyouma

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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vinney12

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Reply 2 on: Mar 21, 2021
Great answer, keep it coming :)


ktidd

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Reply 3 on: Yesterday
:D TYSM

 

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