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Author Question: The reaction H2SeO3(aq) 6I(aq) + 4H+(aq) 2I3(aq) + 3H2O(l) + Se(s) was studied at 0C by the method ... (Read 177 times)

cartlidgeashley

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The reaction H2SeO3(aq) 6I(aq) + 4H+(aq) → 2I3(aq) + 3H2O(l) + Se(s) was studied at 0°C by the method of initial rates:
[H2SeO3]0
[H+]0
[I]0
Rate (mol/L s)
1.0 × 10–4
2.0 × 10–2
2.0 × 10–2
1.66 × 10–7
2.0 × 10–4
2.0 × 10–2
2.0 × 10–2
3.33 × 10–7
3.0 × 10–4
2.0 × 10–2
2.0 × 10–2
4.99 × 10–7
1.0 × 10–4
4.0 × 10–2
2.0 × 10–2
6.66 × 10–7
1.0 × 10–4
1.0 × 10–2
2.0 × 10–2
0.41 × 10–7
1.0 × 10–4
2.0 × 10–2
4.0 × 10–2
13.4 × 10–7
1.0 × 10–4
  4.0 × 10–2
4.0 × 10–2
5.33 × 10–6

The rate law is

 
Reference: Ref 12-5


Rate = k[H2SeO3][H+][I]
Rate = k[H2SeO3][H+]2[I]
Rate = k[H2SeO3][H+][I]2
Rate = k[H2SeO3]2[H+][I]
Rate = k[H2SeO3][H+]2[I]3



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Marked as best answer by cartlidgeashley on Mar 21, 2021

harveenkau8139

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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cartlidgeashley

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Reply 2 on: Mar 21, 2021
Great answer, keep it coming :)


tandmlomax84

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

 

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