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Author Question: The reaction H2SeO3(aq) 6I(aq) + 4H+(aq) 2I3(aq) + 3H2O(l) + Se(s) was studied at 0C by the method ... (Read 158 times)

cartlidgeashley

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on: Mar 21, 2021
The reaction H2SeO3(aq) 6I–(aq) + 4H+(aq) → 2I3–(aq) + 3H2O(l) + Se(s) was studied at 0°C by the method of initial rates:
[H2SeO3]0
[H+]0
[I–]0
Rate (mol/L s)
1.0 × 10–4
2.0 × 10–2
2.0 × 10–2
1.66 × 10–7
2.0 × 10–4
2.0 × 10–2
2.0 × 10–2
3.33 × 10–7
3.0 × 10–4
2.0 × 10–2
2.0 × 10–2
4.99 × 10–7
1.0 × 10–4
4.0 × 10–2
2.0 × 10–2
6.66 × 10–7
1.0 × 10–4
1.0 × 10–2
2.0 × 10–2
0.41 × 10–7
1.0 × 10–4
2.0 × 10–2
4.0 × 10–2
13.4 × 10–7
1.0 × 10–4
  4.0 × 10–2
4.0 × 10–2
5.33 × 10–6

​

The rate law is

 
Reference: Ref 12-5

​

​


◦ Rate = k[H2SeO3][H+][I–]
◦ Rate = k[H2SeO3][H+]2[I–]
◦ Rate = k[H2SeO3][H+][I–]2
◦ Rate = k[H2SeO3]2[H+][I–]
◦ Rate = k[H2SeO3][H+]2[I–]3

​

Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by cartlidgeashley on Mar 21, 2021

harveenkau8139

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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cartlidgeashley

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Reply 2 on: Mar 21, 2021
:D TYSM

nguyenhoanhat

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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