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Author Question: A 100.-mL sample of a 0.10 M solution of H3PO4 is titrated with 0.20 M NaOH. What volume of base ... (Read 60 times)

maegan_martin

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on: Mar 21, 2021

Question 1

A 100-mL sample of 0.10 M HCl is mixed with 50. mL of 0.12 M NH3. What is the resulting pH? (Kb for NH3 = 1.8 × 10–5)

◦ 3.07
◦ 10.93
◦ 12.43
◦ 1.40
◦ 1.57

Question 2

A 100.-mL sample of a 0.10 M solution of H3PO4 is titrated with 0.20 M NaOH. What volume of base must be added to reach the third equivalence point?

◦ 50. mL
◦ 1.0 × 102

◦ 150 mL
◦ 2.0 × 102

◦ 250 mL
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Marked as best answer by maegan_martin on Mar 21, 2021

IRincones

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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maegan_martin

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Reply 2 on: Mar 21, 2021
Excellent

covalentbond

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Reply 3 on: Yesterday
Gracias!

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