A moving particle starts at an initial position (1, 0, 0) with ...

[nelaaney]

Question 1

Find the acceleration at  time  t = -1  of a particle whose position at time  t  is given by  r(t) = 4t i + t² j.
◦ a(-1) = -2j
◦ a(-1) = i - 2j
◦ a(-1) = i + 2j
◦ a(-1) = 2j
◦ a(-1) = 2i + j

Question 2

A moving particle starts at an initial position  (1, 0, 0) with initial velocity  i - j + k. Its acceleration at time  t  is  a(t) = 4t i + 6t j + k. Find its velocity and position at time  t > 0.
◦ v(t) = (2t² + 1) i + (3t² - 1) j + (t + 1) k;   r(t) = (t³ + t + 1) i + (t³ - t) j + (t² + t) k
◦ v(t) = (2t² - 1) i + (3t² - 1) j - (t + 1) k;   r(t) = (t³ + t + 1) i - (t³ - t) j + (t² + t) k
◦ v(t) = (2t² + 1) i + (3t² - 1) j + (t + 1) k;   r(t) = (t³ + t + 1) i + (t³ - t) j + (t² + t) k
◦ v(t) = (2t² + 1) i + (3t² - 1) j + (t + 1) k;   r(t) = (t³ + t + 1) i + (t³ - t) j - (t² + t) k
◦ v(t) = (2t² + 1) i + (3t² + 2) j + (t + 1) k;   r(t) = (t³ + t + 1) i + (t³ + 2t) j + (t² + t) k

[momtoalll]

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[nelaaney]

Great answer, keep it coming

[kishoreddi]

YES! Correct, THANKS for helping me on my review